Shardul Thakur not playing: India have made a solitary change to their Playing XI for their fourth ICC T20 World Cup 2021 match.
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During the 37th match of the ongoing ICC T20 World Cup 2021 between India and Scotland in Dubai, India captain Virat Kohli has won the toss and chose to field. Having developed a knack of losing tosses in international cricket, Kohli’s luck worked in his favour on his 33rd birthday.
“We are going to bowl first. Dew is going to be a big factor. Try and restrict them and chase it down. Winning my first toss on my birthday, probably we should have played the first game on my birthday [smiles]. The intensity from ball one is important,” Kohli said at the toss.
Scotland captain Kyle Coetzer remained unperturbed about being asked to bat first. Instead, Coetzer sounded excited at the prospect of playing a World Cup T20I against India.
“Looks a good deck. Happy to go either way. First of all great occasion for us and Scottish cricket and the associate game. We are playing against some of the best players from the world here and in the last couple of games too. India is another special occasion for us. We have got to go out there, enjoy ourselves and try and express ourselves as much as possible,” Coetzer said at the toss.
Why is Shardul Thakur not playing vs Scotland?
Despite winning their last match against Afghanistan by 66 runs, India have made a solitary change to their Playing XI by including spinner Varun Chakravarthy for pacer Shardul Thakur. Readers must note that Chakravarthy had missed the last match due to a niggle.
“Shardul [Thakur] makes way for Varun [Chakravarthy]. He is back fit, so he will be our third spinner,” Kohli confirmed India playing an extra spinner at the Dubai International Cricket Stadium tonight.
In the 4.3 overs which Thakur has bowled across two matches in this tournament, he has leaked 48 runs at an economy rate of 10.66 without picking any wicket.
Scotland, on the other hand, will take the field without tinkering with their Playing XI.
