Virat Kohli’s slap shot in 4th ODI vs Australia: The Indian captain had scored an outstanding boundary in the fourth ODI.
During the fourth ODI of the ongoing Australia’s tour of India at Mohali, India captain Virat Kohli played a first-rate boundary which ended up becoming a source of amazement for one and all.
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While one usually associates Kohli with orthodox cricketing shots, the shot witnessed the right-hand batsman trying his hands at an unconventional shot. Having executed it to perfection, Kohli had put on display another facet of his game.
Kohli had come out to bat at No. 4 in the 38th over. It all happened on the last delivery of the 39th over when Kohli walked across the stumps to Australia fast bowler Jason Behrendorff.
In what was a length delivery, Kohli slapped it without even watching the ball as it ended up crossing the fine-leg boundary. Kohli’s shot had left India batsman Lokesh Rahul, who was at the non-striker’s end, surprised as he gave the impression of enjoying the shot.
While Kohli gave positive signs initially, he couldn’t carry on for much longer as he was caught behind off Australia fast bowler Jhye Richardson in the following over. He ended up scoring 7 (6) with the help of one four.
Here’s why Kohli batted at No. 4
The reason why Kohli was demoted down the batting order was that the team management wanted to give more time to Rahul in the middle. Coming in to bat at No. 3 in the 31st over, Rahul didn’t entirely stood tall on the expectations as he ended up scoring 26 (31) with the help of one four.
Despite scoring 358-9 in their allotted quota of 50 overs, India ended up losing the match by 4 wickets. Australia batsman Ashton Turner was declared the ‘Man of the Match’ for playing a match-winning innings in only his second ODI. He scored 84* (43) with the help of five fours and six sixes.
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